(x2-2x)2-8=7(x2-2x)

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Solution for (x2-2x)2-8=7(x2-2x) equation: 



(x2-2x)2-8=7(x2-2x)

We move all terms to the left:

(x2-2x)2-8-(7(x2-2x))=0

We add all the numbers together, and all the variables

(+x^2-2x)2-(7(+x^2-2x))-8=0

We multiply parentheses

2x^2-(7(+x^2-2x))-4x-8=0



We calculate terms in parentheses: -(7(+x^2-2x)), so:

7(+x^2-2x)

We multiply parentheses

7x^2-14x

Back to the equation:

-(7x^2-14x)



We add all the numbers together, and all the variables

2x^2-4x-(7x^2-14x)-8=0

We get rid of parentheses

2x^2-7x^2-4x+14x-8=0

We add all the numbers together, and all the variables

-5x^2+10x-8=0

a = -5; b = 10; c = -8;
Δ = b2-4ac
Δ = 102-4·(-5)·(-8)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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