(x2-4x+3)/(-x2+3x+4)=0

Solution for (x2-4x+3)/(-x2+3x+4)=0 equation:

(x2-4x+3)/(-x2+3x+4)=0


Domain of the equation: (-x2+3x+4)!=0

We move all terms containing x to the left, all other terms to the right

-x2+3x!=-4

x∈R


We add all the numbers together, and all the variables

(+x^2-4x+3)/(-1x^2+3x+4)=0

We multiply all the terms by the denominator


(+x^2-4x+3)=0

We get rid of parentheses

x^2-4x+3=0

a = 1; b = -4; c = +3;
Δ = b2-4ac
Δ = -42-4·1·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2}{2*1}=\frac{2}{2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2}{2*1}=\frac{6}{2}
=3
$