(x4+4x3-x2-16x+12)/(x2+x-6)=2x+2

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Solution for (x4+4x3-x2-16x+12)/(x2+x-6)=2x+2 equation: 



(x4+4x^3-x2-16x+12)/(x2+x-6)=2x+2

We move all terms to the left:

(x4+4x^3-x2-16x+12)/(x2+x-6)-(2x+2)=0

We do not support expression: x^3

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