(x=10)+(3x-5)+x=180

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Solution for (x=10)+(3x-5)+x=180 equation: 



(x=10)+(3x-5)+x=180

We move all terms to the left:

(x-(10)+(3x-5)+x)=0



We calculate terms in parentheses: +(x-10+(3x-5)+x), so:

x-10+(3x-5)+x

determiningTheFunctionDomain
x+(3x-5)+x-10

We add all the numbers together, and all the variables

2x+(3x-5)-10

We get rid of parentheses

2x+3x-5-10

We add all the numbers together, and all the variables

5x-15

Back to the equation:

+(5x-15)



We get rid of parentheses

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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