(x=40)+(3x-17)+(2x-5)=180

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Solution for (x=40)+(3x-17)+(2x-5)=180 equation: 



(x=40)+(3x-17)+(2x-5)=180

We move all terms to the left:

(x-(40)+(3x-17)+(2x-5))=0



We calculate terms in parentheses: +(x-40+(3x-17)+(2x-5)), so:

x-40+(3x-17)+(2x-5)

determiningTheFunctionDomain
x+(3x-17)+(2x-5)-40

We get rid of parentheses

x+3x+2x-17-5-40

We add all the numbers together, and all the variables

6x-62

Back to the equation:

+(6x-62)



We get rid of parentheses

6x-62=0

We move all terms containing x to the left, all other terms to the right

6x=62

x=62/6

x=10+1/3

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