(x=9)(6x-1)(8x+4)=0

Solution for (x=9)(6x-1)(8x+4)=0 equation:

(x=9)(6x-1)(8x+4)=0

We move all terms to the left:

(x-(9)(6x-1)(8x+4))=0

We multiply parentheses ..

(x-9(+48x^2+24x-8x-4))=0


We calculate terms in parentheses: +(x-9(+48x^2+24x-8x-4)), so:

x-9(+48x^2+24x-8x-4)

determiningTheFunctionDomain
-9(+48x^2+24x-8x-4)+x

We multiply parentheses

-432x^2-216x+72x+x+36

We add all the numbers together, and all the variables

-432x^2-143x+36

Back to the equation:

+(-432x^2-143x+36)


We get rid of parentheses

-432x^2-143x+36=0

a = -432; b = -143; c = +36;
Δ = b2-4ac
Δ = -1432-4·(-432)·36
Δ = 82657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-143)-\sqrt{82657}}{2*-432}=\frac{143-\sqrt{82657}}{-864}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-143)+\sqrt{82657}}{2*-432}=\frac{143+\sqrt{82657}}{-864}
$