(y+1)(3y+3)=

Solution for (y+1)(3y+3)= equation:

Simplifying
(y + 1)(3y + 3) = 0

Reorder the terms:
(1 + y)(3y + 3) = 0

Reorder the terms:
(1 + y)(3 + 3y) = 0

Multiply (1 + y) * (3 + 3y)
(1(3 + 3y) + y(3 + 3y)) = 0
((3 * 1 + 3y * 1) + y(3 + 3y)) = 0
((3 + 3y) + y(3 + 3y)) = 0
(3 + 3y + (3 * y + 3y * y)) = 0
(3 + 3y + (3y + 3y2)) = 0

Combine like terms: 3y + 3y = 6y
(3 + 6y + 3y2) = 0

Solving
3 + 6y + 3y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '3'.
3(1 + 2y + y2) = 0

Factor a trinomial.
3((1 + y)(1 + y)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(1 + y)' equal to zero and attempt to solve:

Simplifying
1 + y = 0

Solving
1 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + y = 0 + -1
y = 0 + -1

Combine like terms: 0 + -1 = -1
y = -1

Simplifying
y = -1
Subproblem 2
Set the factor '(1 + y)' equal to zero and attempt to solve:

Simplifying
1 + y = 0

Solving
1 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + y = 0 + -1
y = 0 + -1

Combine like terms: 0 + -1 = -1
y = -1

Simplifying
y = -1
Solution
y = {-1, -1}