(y+1/3)+(y-2/2)=2

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Solution for (y+1/3)+(y-2/2)=2 equation:



(y+1/3)+(y-2/2)=2
We move all terms to the left:
(y+1/3)+(y-2/2)-(2)=0
We add all the numbers together, and all the variables
(+y+1/3)+(y-1)-2=0
We get rid of parentheses
y+y-1-2+1/3=0
We multiply all the terms by the denominator
y*3+y*3+1-1*3-2*3=0
We add all the numbers together, and all the variables
y*3+y*3-8=0
Wy multiply elements
3y+3y-8=0
We add all the numbers together, and all the variables
6y-8=0
We move all terms containing y to the left, all other terms to the right
6y=8
y=8/6
y=1+1/3

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