(y+2)(3+1y)=

Solution for (y+2)(3+1y)= equation:

Simplifying
(y + 2)(3 + 1y) = 0

Reorder the terms:
(2 + y)(3 + 1y) = 0

Multiply (2 + y) * (3 + 1y)
(2(3 + 1y) + y(3 + 1y)) = 0
((3 * 2 + 1y * 2) + y(3 + 1y)) = 0
((6 + 2y) + y(3 + 1y)) = 0
(6 + 2y + (3 * y + 1y * y)) = 0
(6 + 2y + (3y + 1y2)) = 0

Combine like terms: 2y + 3y = 5y
(6 + 5y + 1y2) = 0

Solving
6 + 5y + 1y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(3 + y)(2 + y) = 0

Subproblem 1
Set the factor '(3 + y)' equal to zero and attempt to solve:

Simplifying
3 + y = 0

Solving
3 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + y = 0 + -3
y = 0 + -3

Combine like terms: 0 + -3 = -3
y = -3

Simplifying
y = -3
Subproblem 2
Set the factor '(2 + y)' equal to zero and attempt to solve:

Simplifying
2 + y = 0

Solving
2 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + y = 0 + -2
y = 0 + -2

Combine like terms: 0 + -2 = -2
y = -2

Simplifying
y = -2
Solution
y = {-3, -2}