(y+2)(y+2)+120=0

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Solution for (y+2)(y+2)+120=0 equation:


Simplifying
(y + 2)(y + 2) + 120 = 0

Reorder the terms:
(2 + y)(y + 2) + 120 = 0

Reorder the terms:
(2 + y)(2 + y) + 120 = 0

Multiply (2 + y) * (2 + y)
(2(2 + y) + y(2 + y)) + 120 = 0
((2 * 2 + y * 2) + y(2 + y)) + 120 = 0
((4 + 2y) + y(2 + y)) + 120 = 0
(4 + 2y + (2 * y + y * y)) + 120 = 0
(4 + 2y + (2y + y2)) + 120 = 0

Combine like terms: 2y + 2y = 4y
(4 + 4y + y2) + 120 = 0

Reorder the terms:
4 + 120 + 4y + y2 = 0

Combine like terms: 4 + 120 = 124
124 + 4y + y2 = 0

Solving
124 + 4y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-124' to each side of the equation.
124 + 4y + -124 + y2 = 0 + -124

Reorder the terms:
124 + -124 + 4y + y2 = 0 + -124

Combine like terms: 124 + -124 = 0
0 + 4y + y2 = 0 + -124
4y + y2 = 0 + -124

Combine like terms: 0 + -124 = -124
4y + y2 = -124

The y term is 4y.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4y + 4 + y2 = -124 + 4

Reorder the terms:
4 + 4y + y2 = -124 + 4

Combine like terms: -124 + 4 = -120
4 + 4y + y2 = -120

Factor a perfect square on the left side:
(y + 2)(y + 2) = -120

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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