(y+2)(y+7)=y2+32

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Solution for (y+2)(y+7)=y2+32 equation: 



(y+2)(y+7)=y2+32

We move all terms to the left:

(y+2)(y+7)-(y2+32)=0

We add all the numbers together, and all the variables

-(+y^2+32)+(y+2)(y+7)=0

We get rid of parentheses

-y^2+(y+2)(y+7)-32=0

We multiply parentheses ..

-y^2+(+y^2+7y+2y+14)-32=0

We add all the numbers together, and all the variables

-1y^2+(+y^2+7y+2y+14)-32=0

We get rid of parentheses

-1y^2+y^2+7y+2y+14-32=0

We add all the numbers together, and all the variables

9y-18=0

We move all terms containing y to the left, all other terms to the right

9y=18

y=18/9

y=2

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