(y+2)(y-3)=y2

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Solution for (y+2)(y-3)=y2 equation: 



(y+2)(y-3)=y2

We move all terms to the left:

(y+2)(y-3)-(y2)=0

We add all the numbers together, and all the variables

-1y^2+(y+2)(y-3)=0

We multiply parentheses ..

-1y^2+(+y^2-3y+2y-6)=0

We get rid of parentheses

-1y^2+y^2-3y+2y-6=0

We add all the numbers together, and all the variables

-1y-6=0

We move all terms containing y to the left, all other terms to the right

-y=6

y=6/-1

y=-6

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