(y+2)+2y=7(y-1)+9

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Solution for (y+2)+2y=7(y-1)+9 equation: 



(y+2)+2y=7(y-1)+9

We move all terms to the left:

(y+2)+2y-(7(y-1)+9)=0

We add all the numbers together, and all the variables

2y+(y+2)-(7(y-1)+9)=0

We get rid of parentheses

2y+y-(7(y-1)+9)+2=0



We calculate terms in parentheses: -(7(y-1)+9), so:

7(y-1)+9

We multiply parentheses

7y-7+9

We add all the numbers together, and all the variables

7y+2

Back to the equation:

-(7y+2)



We add all the numbers together, and all the variables

3y-(7y+2)+2=0

We get rid of parentheses

3y-7y-2+2=0

We add all the numbers together, and all the variables

-4y=0

y=0/-4

y=0

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