(y+2)-(3y-4)=-4

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Solution for (y+2)-(3y-4)=-4 equation: 



(y+2)-(3y-4)=-4

We move all terms to the left:

(y+2)-(3y-4)-(-4)=0

We add all the numbers together, and all the variables

(y+2)-(3y-4)+4=0

We get rid of parentheses

y-3y+2+4+4=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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