(y+2)/3=(6y+5)/4

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Solution for (y+2)/3=(6y+5)/4 equation: 



(y+2)/3=(6y+5)/4

We move all terms to the left:

(y+2)/3-((6y+5)/4)=0

We calculate fractions


y/()+(-((6y+5)*3)/()=0



We calculate terms in parentheses: +(-((6y+5)*3)/(), so:

-((6y+5)*3)/(

We multiply all the terms by the denominator


-((6y+5)*3)



We calculate terms in parentheses: -((6y+5)*3), so:

(6y+5)*3

We multiply parentheses

18y+15

Back to the equation:

-(18y+15)



We get rid of parentheses

-18y-15

Back to the equation:

+(-18y-15)



We get rid of parentheses

y/()-18y-15=0

We multiply all the terms by the denominator


y-18y*()-15*()=0

We add all the numbers together, and all the variables

y-18y*()=0

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