(y+2/y+5)-2

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Solution for (y+2/y+5)-2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y+2/y-2+5 = 0

1*y^1+2*y^-1+3*y^0 = 0

(1*y^2+3*y^1+2*y^0)/(y^1) = 0 // * y^2

y^1*(1*y^2+3*y^1+2*y^0) = 0

y^1

y^2+3*y+2 = 0

y^2+3*y+2 = 0

DELTA = 3^2-(1*2*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)-3)/(1*2) or y = (-1^(1/2)-3)/(1*2)

y = -1 or y = -2

y in { -2, -1} 

y in { -2, -1 }

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