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(y+3)(240y-1)=240
We move all terms to the left:
(y+3)(240y-1)-(240)=0
We multiply parentheses ..
(+240y^2-1y+720y-3)-240=0
We get rid of parentheses
240y^2-1y+720y-3-240=0
We add all the numbers together, and all the variables
240y^2+719y-243=0
a = 240; b = 719; c = -243;
Δ = b2-4ac
Δ = 7192-4·240·(-243)
Δ = 750241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(719)-\sqrt{750241}}{2*240}=\frac{-719-\sqrt{750241}}{480} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(719)+\sqrt{750241}}{2*240}=\frac{-719+\sqrt{750241}}{480} $
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