(y+3)(y+4)=0

Solution for (y+3)(y+4)=0 equation:

Simplifying
(y + 3)(y + 4) = 0

Reorder the terms:
(3 + y)(y + 4) = 0

Reorder the terms:
(3 + y)(4 + y) = 0

Multiply (3 + y) * (4 + y)
(3(4 + y) + y(4 + y)) = 0
((4 * 3 + y * 3) + y(4 + y)) = 0
((12 + 3y) + y(4 + y)) = 0
(12 + 3y + (4 * y + y * y)) = 0
(12 + 3y + (4y + y2)) = 0

Combine like terms: 3y + 4y = 7y
(12 + 7y + y2) = 0

Solving
12 + 7y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(4 + y)(3 + y) = 0

Subproblem 1
Set the factor '(4 + y)' equal to zero and attempt to solve:

Simplifying
4 + y = 0

Solving
4 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + y = 0 + -4
y = 0 + -4

Combine like terms: 0 + -4 = -4
y = -4

Simplifying
y = -4
Subproblem 2
Set the factor '(3 + y)' equal to zero and attempt to solve:

Simplifying
3 + y = 0

Solving
3 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + y = 0 + -3
y = 0 + -3

Combine like terms: 0 + -3 = -3
y = -3

Simplifying
y = -3
Solution
y = {-4, -3}