(y+3)/2=(y-4)/6

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Solution for (y+3)/2=(y-4)/6 equation: 



(y+3)/2=(y-4)/6

We move all terms to the left:

(y+3)/2-((y-4)/6)=0

We calculate fractions


y/()+(-((y-4)*2)/()=0



We calculate terms in parentheses: +(-((y-4)*2)/(), so:

-((y-4)*2)/(

We multiply all the terms by the denominator


-((y-4)*2)



We calculate terms in parentheses: -((y-4)*2), so:

(y-4)*2

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

-2y+8

Back to the equation:

+(-2y+8)



We get rid of parentheses

y/()-2y+8=0

We multiply all the terms by the denominator


y-2y*()+8*()=0

We add all the numbers together, and all the variables

y-2y*()=0

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