(y+3)=2(3+y)

Solution for (y+3)=2(3+y) equation:

(y+3)=2(3+y)

We move all terms to the left:

(y+3)-(2(3+y))=0

We add all the numbers together, and all the variables

(y+3)-(2(y+3))=0

We get rid of parentheses

y-(2(y+3))+3=0


We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)


We get rid of parentheses

y-2y-6+3=0

We add all the numbers together, and all the variables

-1y-3=0

We move all terms containing y to the left, all other terms to the right

-y=3

y=3/-1

y=-3