(y+30)+(4y+30)+(10y-30)=180

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Solution for (y+30)+(4y+30)+(10y-30)=180 equation: 



(y+30)+(4y+30)+(10y-30)=180

We move all terms to the left:

(y+30)+(4y+30)+(10y-30)-(180)=0

We get rid of parentheses

y+4y+10y+30+30-30-180=0

We add all the numbers together, and all the variables

15y-150=0

We move all terms containing y to the left, all other terms to the right

15y=150

y=150/15

y=10

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