(y+30)+(y+30)=(3y+12)

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Solution for (y+30)+(y+30)=(3y+12) equation: 



(y+30)+(y+30)=(3y+12)

We move all terms to the left:

(y+30)+(y+30)-((3y+12))=0

We get rid of parentheses

y+y-((3y+12))+30+30=0



We calculate terms in parentheses: -((3y+12)), so:

(3y+12)

We get rid of parentheses

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

2y-(3y+12)+60=0

We get rid of parentheses

2y-3y-12+60=0

We add all the numbers together, and all the variables

-1y+48=0

We move all terms containing y to the left, all other terms to the right

-y=-48

y=-48/-1

y=+48

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