(y+30)+(y+30)=180-(3y+12)

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Solution for (y+30)+(y+30)=180-(3y+12) equation: 



(y+30)+(y+30)=180-(3y+12)

We move all terms to the left:

(y+30)+(y+30)-(180-(3y+12))=0

We get rid of parentheses

y+y-(180-(3y+12))+30+30=0



We calculate terms in parentheses: -(180-(3y+12)), so:

180-(3y+12)

determiningTheFunctionDomain
-(3y+12)+180

We get rid of parentheses

-3y-12+180

We add all the numbers together, and all the variables

-3y+168

Back to the equation:

-(-3y+168)



We add all the numbers together, and all the variables

2y-(-3y+168)+60=0

We get rid of parentheses

2y+3y-168+60=0

We add all the numbers together, and all the variables

5y-108=0

We move all terms containing y to the left, all other terms to the right

5y=108

y=108/5

y=21+3/5

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