(y+30)+(y+30)=180-(3y-12)

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Solution for (y+30)+(y+30)=180-(3y-12) equation: 



(y+30)+(y+30)=180-(3y-12)

We move all terms to the left:

(y+30)+(y+30)-(180-(3y-12))=0

We get rid of parentheses

y+y-(180-(3y-12))+30+30=0



We calculate terms in parentheses: -(180-(3y-12)), so:

180-(3y-12)

determiningTheFunctionDomain
-(3y-12)+180

We get rid of parentheses

-3y+12+180

We add all the numbers together, and all the variables

-3y+192

Back to the equation:

-(-3y+192)



We add all the numbers together, and all the variables

2y-(-3y+192)+60=0

We get rid of parentheses

2y+3y-192+60=0

We add all the numbers together, and all the variables

5y-132=0

We move all terms containing y to the left, all other terms to the right

5y=132

y=132/5

y=26+2/5

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