(y+4)(y-2)=(y-2)(y+4)

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Solution for (y+4)(y-2)=(y-2)(y+4) equation: 



(y+4)(y-2)=(y-2)(y+4)

We move all terms to the left:

(y+4)(y-2)-((y-2)(y+4))=0

We multiply parentheses ..

(+y^2-2y+4y-8)-((y-2)(y+4))=0



We calculate terms in parentheses: -((y-2)(y+4)), so:

(y-2)(y+4)

We multiply parentheses ..

(+y^2+4y-2y-8)

We get rid of parentheses

y^2+4y-2y-8

We add all the numbers together, and all the variables

y^2+2y-8

Back to the equation:

-(y^2+2y-8)



We get rid of parentheses

y^2-y^2-2y+4y-2y-8+8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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