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(y+4)=(y+1)
We move all terms to the left:
(y+4)-((y+1))=0
We get rid of parentheses
y-((y+1))+4=0
We calculate terms in parentheses: -((y+1)), so:We get rid of parentheses
(y+1)
We get rid of parentheses
y+1
Back to the equation:
-(y+1)
y-y-1+4=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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