(y+5)(y+3)=(y+1)

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Solution for (y+5)(y+3)=(y+1) equation: 



(y+5)(y+3)=(y+1)

We move all terms to the left:

(y+5)(y+3)-((y+1))=0

We multiply parentheses ..

(+y^2+3y+5y+15)-((y+1))=0



We calculate terms in parentheses: -((y+1)), so:

(y+1)

We get rid of parentheses

y+1

Back to the equation:

-(y+1)



We get rid of parentheses

y^2+3y+5y-y+15-1=0

We add all the numbers together, and all the variables

y^2+7y+14=0

a = 1; b = 7; c = +14;
Δ = b2-4ac
Δ = 72-4·1·14
Δ = -7
Delta is less than zero, so there is no solution for the equation

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