(y+5)(y+3)=(y+1)(y+5)

Solution for (y+5)(y+3)=(y+1)(y+5) equation:

(y+5)(y+3)=(y+1)(y+5)

We move all terms to the left:

(y+5)(y+3)-((y+1)(y+5))=0

We multiply parentheses ..

(+y^2+3y+5y+15)-((y+1)(y+5))=0


We calculate terms in parentheses: -((y+1)(y+5)), so:

(y+1)(y+5)

We multiply parentheses ..

(+y^2+5y+y+5)

We get rid of parentheses

y^2+5y+y+5

We add all the numbers together, and all the variables

y^2+6y+5

Back to the equation:

-(y^2+6y+5)


We get rid of parentheses

y^2-y^2+3y+5y-6y+15-5=0

We add all the numbers together, and all the variables

2y+10=0

We move all terms containing y to the left, all other terms to the right

2y=-10

y=-10/2

y=-5