(y+5)(y-2)=(y-5)(y+3)

Solution for (y+5)(y-2)=(y-5)(y+3) equation:

(y+5)(y-2)=(y-5)(y+3)

We move all terms to the left:

(y+5)(y-2)-((y-5)(y+3))=0

We multiply parentheses ..

(+y^2-2y+5y-10)-((y-5)(y+3))=0


We calculate terms in parentheses: -((y-5)(y+3)), so:

(y-5)(y+3)

We multiply parentheses ..

(+y^2+3y-5y-15)

We get rid of parentheses

y^2+3y-5y-15

We add all the numbers together, and all the variables

y^2-2y-15

Back to the equation:

-(y^2-2y-15)


We get rid of parentheses

y^2-y^2-2y+5y+2y-10+15=0

We add all the numbers together, and all the variables

5y+5=0

We move all terms containing y to the left, all other terms to the right

5y=-5

y=-5/5

y=-1