(y+5/y-3)=(y-1/y-4)+1

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Solution for (y+5/y-3)=(y-1/y-4)+1 equation: 



(y+5/y-3)=(y-1/y-4)+1

We move all terms to the left:

(y+5/y-3)-((y-1/y-4)+1)=0



Domain of the equation: y-3)!=0

y∈R





Domain of the equation: y-4)+1)!=0

y∈R



We get rid of parentheses

y+5/y-((y-1/y-4)+1)-3=0

We calculate fractions


y+5y/y^2+(-((y-1*y)/y^2-3=0

We add all the numbers together, and all the variables

y+5y/y^2+(-(0/y^2-3=0

We calculate fractions

We do not support eypression: y^4

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