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(y+9)(y+13)=0
We multiply parentheses ..
(+y^2+13y+9y+117)=0
We get rid of parentheses
y^2+13y+9y+117=0
We add all the numbers together, and all the variables
y^2+22y+117=0
a = 1; b = 22; c = +117;
Δ = b2-4ac
Δ = 222-4·1·117
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-4}{2*1}=\frac{-26}{2} =-13 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+4}{2*1}=\frac{-18}{2} =-9 $
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