(y+Z)(y+z)=2yz

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Solution for (y+Z)(y+z)=2yz equation:


Simplifying
(y + Z)(y + z) = 2yz

Reorder the terms:
(Z + y)(y + z) = 2yz

Multiply (Z + y) * (y + z)
(Z(y + z) + y(y + z)) = 2yz
((y * Z + z * Z) + y(y + z)) = 2yz
((yZ + zZ) + y(y + z)) = 2yz
(yZ + zZ + (y * y + z * y)) = 2yz

Reorder the terms:
(yZ + zZ + (yz + y2)) = 2yz
(yZ + zZ + (yz + y2)) = 2yz

Reorder the terms:
(yZ + yz + y2 + zZ) = 2yz
(yZ + yz + y2 + zZ) = 2yz

Solving
yZ + yz + y2 + zZ = 2yz

Solving for variable 'y'.

Reorder the terms:
yZ + yz + -2yz + y2 + zZ = 2yz + -2yz

Combine like terms: yz + -2yz = -1yz
yZ + -1yz + y2 + zZ = 2yz + -2yz

Combine like terms: 2yz + -2yz = 0
yZ + -1yz + y2 + zZ = 0

The solution to this equation could not be determined.

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