(y-1)/(y+2)=1-(2/y)

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Solution for (y-1)/(y+2)=1-(2/y) equation: 


D( y )

y = 0

y+2 = 0

y = 0

y = 0

y+2 = 0

y+2 = 0

y+2 = 0 // - 2

y = -2

y in (-oo:-2) U (-2:0) U (0:+oo)

(y-1)/(y+2) = 1-(2/y) // - 1-(2/y)

(y-1)/(y+2)+2/y-1 = 0

(y*(y-1))/(y*(y+2))+(2*(y+2))/(y*(y+2))+(-1*y*(y+2))/(y*(y+2)) = 0

y*(y-1)+2*(y+2)-1*y*(y+2) = 0

y^2-y^2+y-2*y+4 = 0

4-y = 0

(4-y)/(y*(y+2)) = 0

(4-y)/(y*(y+2)) = 0 // * y*(y+2)

4-y = 0

4-y = 0 // - 4

-y = -4 // * -1

y = 4

y = 4

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