(y-1)/2+(y+1)/3=(2y+5)/6

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Solution for (y-1)/2+(y+1)/3=(2y+5)/6 equation: 


y in (-oo:+oo)

(y-1)/2+(y+1)/3 = (2*y+5)/6 // - (2*y+5)/6

(y-1)/2+(y+1)/3-((2*y+5)/6) = 0

(y-1)/2+(y+1)/3+(-1*(2*y+5))/6 = 0

(3*6*(y-1))/(2*3*6)+(2*6*(y+1))/(2*3*6)+(-1*2*3*(2*y+5))/(2*3*6) = 0

3*6*(y-1)+2*6*(y+1)-1*2*3*(2*y+5) = 0

30*y-12*y-30-6 = 0

18*y-36 = 0

(18*y-36)/(2*3*6) = 0

(18*y-36)/(2*3*6) = 0 // * 2*3*6

18*y-36 = 0

18*y-36 = 0 // + 36

18*y = 36 // : 18

y = 36/18

y = 2

y = 2

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