(y-1/y-7)+1=y-4/y-3

Solution for (y-1/y-7)+1=y-4/y-3 equation:

(y-1/y-7)+1=y-4/y-3

We move all terms to the left:

(y-1/y-7)+1-(y-4/y-3)=0


Domain of the equation: y-7)!=0

y∈R



Domain of the equation: y-3)!=0

y∈R


We get rid of parentheses

y-1/y-y+4/y-7+3+1=0

We multiply all the terms by the denominator


y*y-y*y-7*y+3*y+1*y-1+4=0

We add all the numbers together, and all the variables

-3y+y*y-y*y+3=0

Wy multiply elements

y^2-1y^2-3y+3=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1