(y-12)(y-1)=0

Solution for (y-12)(y-1)=0 equation:

Simplifying
(y + -12)(y + -1) = 0

Reorder the terms:
(-12 + y)(y + -1) = 0

Reorder the terms:
(-12 + y)(-1 + y) = 0

Multiply (-12 + y) * (-1 + y)
(-12(-1 + y) + y(-1 + y)) = 0
((-1 * -12 + y * -12) + y(-1 + y)) = 0
((12 + -12y) + y(-1 + y)) = 0
(12 + -12y + (-1 * y + y * y)) = 0
(12 + -12y + (-1y + y2)) = 0

Combine like terms: -12y + -1y = -13y
(12 + -13y + y2) = 0

Solving
12 + -13y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + -1y)(12 + -1y) = 0

Subproblem 1
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Subproblem 2
Set the factor '(12 + -1y)' equal to zero and attempt to solve:

Simplifying
12 + -1y = 0

Solving
12 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1y = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1y = 0 + -12
-1y = 0 + -12

Combine like terms: 0 + -12 = -12
-1y = -12

Divide each side by '-1'.
y = 12

Simplifying
y = 12
Solution
y = {1, 12}