(y-13)(y-13)=0

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Solution for (y-13)(y-13)=0 equation: 



(y-13)(y-13)=0

We multiply parentheses ..

(+y^2-13y-13y+169)=0

We get rid of parentheses

y^2-13y-13y+169=0

We add all the numbers together, and all the variables

y^2-26y+169=0

a = 1; b = -26; c = +169;
Δ = b2-4ac
Δ = -262-4·1·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{26}{2}=13$

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