(y-2)(y+2)=0

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Solution for (y-2)(y+2)=0 equation:


Simplifying
(y + -2)(y + 2) = 0

Reorder the terms:
(-2 + y)(y + 2) = 0

Reorder the terms:
(-2 + y)(2 + y) = 0

Multiply (-2 + y) * (2 + y)
(-2(2 + y) + y(2 + y)) = 0
((2 * -2 + y * -2) + y(2 + y)) = 0
((-4 + -2y) + y(2 + y)) = 0
(-4 + -2y + (2 * y + y * y)) = 0
(-4 + -2y + (2y + y2)) = 0

Combine like terms: -2y + 2y = 0
(-4 + 0 + y2) = 0
(-4 + y2) = 0

Solving
-4 + y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + y2 = 0 + 4
y2 = 0 + 4

Combine like terms: 0 + 4 = 4
y2 = 4

Simplifying
y2 = 4

Take the square root of each side:
y = {-2, 2}

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