(y-2)2+(y+4)2=8

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Solution for (y-2)2+(y+4)2=8 equation: 



(y-2)2+(y+4)2=8

We move all terms to the left:

(y-2)2+(y+4)2-(8)=0

We multiply parentheses

2y+2y-4+8-8=0

We add all the numbers together, and all the variables

4y-4=0

We move all terms containing y to the left, all other terms to the right

4y=4

y=4/4

y=1

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