(y-3)(y+1)=

Solution for (y-3)(y+1)= equation:

Simplifying
(y + -3)(y + 1) = 0

Reorder the terms:
(-3 + y)(y + 1) = 0

Reorder the terms:
(-3 + y)(1 + y) = 0

Multiply (-3 + y) * (1 + y)
(-3(1 + y) + y(1 + y)) = 0
((1 * -3 + y * -3) + y(1 + y)) = 0
((-3 + -3y) + y(1 + y)) = 0
(-3 + -3y + (1 * y + y * y)) = 0
(-3 + -3y + (1y + y2)) = 0

Combine like terms: -3y + 1y = -2y
(-3 + -2y + y2) = 0

Solving
-3 + -2y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -1y)(3 + -1y) = 0

Subproblem 1
Set the factor '(-1 + -1y)' equal to zero and attempt to solve:

Simplifying
-1 + -1y = 0

Solving
-1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1y = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1y = 0 + 1
-1y = 0 + 1

Combine like terms: 0 + 1 = 1
-1y = 1

Divide each side by '-1'.
y = -1

Simplifying
y = -1
Subproblem 2
Set the factor '(3 + -1y)' equal to zero and attempt to solve:

Simplifying
3 + -1y = 0

Solving
3 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1y = 0 + -3
-1y = 0 + -3

Combine like terms: 0 + -3 = -3
-1y = -3

Divide each side by '-1'.
y = 3

Simplifying
y = 3
Solution
y = {-1, 3}