(y-3)(y-3)-y(y+5)=6

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Solution for (y-3)(y-3)-y(y+5)=6 equation:



(y-3)(y-3)-y(y+5)=6
We move all terms to the left:
(y-3)(y-3)-y(y+5)-(6)=0
We multiply parentheses
-y^2+(y-3)(y-3)-5y-6=0
We multiply parentheses ..
-y^2+(+y^2-3y-3y+9)-5y-6=0
We add all the numbers together, and all the variables
-1y^2+(+y^2-3y-3y+9)-5y-6=0
We get rid of parentheses
-1y^2+y^2-3y-3y-5y+9-6=0
We add all the numbers together, and all the variables
-11y+3=0
We move all terms containing y to the left, all other terms to the right
-11y=-3
y=-3/-11
y=3/11

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