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(y-3)/(2)+2y=6
We move all terms to the left:
(y-3)/(2)+2y-(6)=0
We add all the numbers together, and all the variables
2y+(y-3)/2-6=0
We multiply all the terms by the denominator
2y*2+(y-3)-6*2=0
We add all the numbers together, and all the variables
2y*2+(y-3)-12=0
Wy multiply elements
4y+(y-3)-12=0
We get rid of parentheses
4y+y-3-12=0
We add all the numbers together, and all the variables
5y-15=0
We move all terms containing y to the left, all other terms to the right
5y=15
y=15/5
y=3
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