(y-3)/4-(y+2)/12=(3y-4)/12

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Solution for (y-3)/4-(y+2)/12=(3y-4)/12 equation: 


y in (-oo:+oo)

(y-3)/4-((y+2)/12) = (3*y-4)/12 // - (3*y-4)/12

(y-3)/4-((y+2)/12)-((3*y-4)/12) = 0

(y-3)/4+(-1*(y+2))/12+(-1*(3*y-4))/12 = 0

(12*(y-3))/(4*12)+(-1*4*(y+2))/(4*12)+(-1*4*(3*y-4))/(4*12) = 0

12*(y-3)-1*4*(y+2)-1*4*(3*y-4) = 0

8*y-12*y-44+16 = 0

-4*y-28 = 0

(-4*y-28)/(4*12) = 0

(-4*y-28)/(4*12) = 0 // * 4*12

-4*y-28 = 0

-4*y-28 = 0 // + 28

-4*y = 28 // : -4

y = 28/(-4)

y = -7

y = -7

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