(y-3/4y)+(y+6/y)=

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Solution for (y-3/4y)+(y+6/y)= equation:



(y-3/4y)+(y+6/y)=
We move all terms to the left:
(y-3/4y)+(y+6/y)-()=0
Domain of the equation: 4y)!=0
y!=0/1
y!=0
y∈R
Domain of the equation: y)!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
(+y-3/4y)+(+y+6/y)-()=0
We add all the numbers together, and all the variables
(+y-3/4y)+(+y+6/y)=0
We get rid of parentheses
y-3/4y+y+6/y=0
We calculate fractions
y+y+(-3y)/4y^2+24y/4y^2=0
We add all the numbers together, and all the variables
2y+(-3y)/4y^2+24y/4y^2=0
We multiply all the terms by the denominator
2y*4y^2+(-3y)+24y=0
We add all the numbers together, and all the variables
24y+2y*4y^2+(-3y)=0
Wy multiply elements
8y^3+24y+(-3y)=0
We get rid of parentheses
8y^3+24y-3y=0
We do not support eypression: y^3

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