(y-4)(y-3)=-2

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Solution for (y-4)(y-3)=-2 equation: 



(y-4)(y-3)=-2

We move all terms to the left:

(y-4)(y-3)-(-2)=0

We add all the numbers together, and all the variables

(y-4)(y-3)+2=0

We multiply parentheses ..

(+y^2-3y-4y+12)+2=0

We get rid of parentheses

y^2-3y-4y+12+2=0

We add all the numbers together, and all the variables

y^2-7y+14=0

a = 1; b = -7; c = +14;
Δ = b2-4ac
Δ = -72-4·1·14
Δ = -7
Delta is less than zero, so there is no solution for the equation

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