(y-4)*2+(y+1)*2=(y-2)*2+(y+6)+3

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Solution for (y-4)*2+(y+1)*2=(y-2)*2+(y+6)+3 equation:


(y-4)*2+(y+1)*2=(y-2)*2+(y+6)+3

We simplify the equation to the form, which is simple to understand 
(y-4)*2+(y+1)*2=(y-2)*2+(y+6)+3

Reorder the terms in parentheses
(+2y-8)+(y+1)*2=(y-2)*2+(y+6)+3

Remove unnecessary parentheses
+2y-8+(y+1)*2=(y-2)*2+(y+6)+3

Reorder the terms in parentheses
+2y-8+(+2y+2)=(y-2)*2+(y+6)+3

Remove unnecessary parentheses
+2y-8+2y+2=+(+y-2+)+*2+(+y+6+)+3

Reorder the terms in parentheses
+2y-8+2y+2=(+2y-4)+(y+6)+3

Remove unnecessary parentheses
+2y-8+2y+2=+2y-4+(y+6)+3

Remove unnecessary parentheses
+2y-8+2y+2=+2y-4+y+6+3

We move all terms containing y to the left and all other terms to the right. 
+2y+2y-2y-1y=-4+6+3+8-2

We simplify left and right side of the equation. 
+1y=+11

We divide both sides of the equation by 1 to get y. 
y=11

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