(y-4)+(y+1)=(y-2)+(y+6)

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Solution for (y-4)+(y+1)=(y-2)+(y+6) equation:


Simplifying
(y + -4) + (y + 1) = (y + -2) + (y + 6)

Reorder the terms:
(-4 + y) + (y + 1) = (y + -2) + (y + 6)

Remove parenthesis around (-4 + y)
-4 + y + (y + 1) = (y + -2) + (y + 6)

Reorder the terms:
-4 + y + (1 + y) = (y + -2) + (y + 6)

Remove parenthesis around (1 + y)
-4 + y + 1 + y = (y + -2) + (y + 6)

Reorder the terms:
-4 + 1 + y + y = (y + -2) + (y + 6)

Combine like terms: -4 + 1 = -3
-3 + y + y = (y + -2) + (y + 6)

Combine like terms: y + y = 2y
-3 + 2y = (y + -2) + (y + 6)

Reorder the terms:
-3 + 2y = (-2 + y) + (y + 6)

Remove parenthesis around (-2 + y)
-3 + 2y = -2 + y + (y + 6)

Reorder the terms:
-3 + 2y = -2 + y + (6 + y)

Remove parenthesis around (6 + y)
-3 + 2y = -2 + y + 6 + y

Reorder the terms:
-3 + 2y = -2 + 6 + y + y

Combine like terms: -2 + 6 = 4
-3 + 2y = 4 + y + y

Combine like terms: y + y = 2y
-3 + 2y = 4 + 2y

Add '-2y' to each side of the equation.
-3 + 2y + -2y = 4 + 2y + -2y

Combine like terms: 2y + -2y = 0
-3 + 0 = 4 + 2y + -2y
-3 = 4 + 2y + -2y

Combine like terms: 2y + -2y = 0
-3 = 4 + 0
-3 = 4

Solving
-3 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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