(y-4)-2(4-y)=1

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Solution for (y-4)-2(4-y)=1 equation: 



(y-4)-2(4-y)=1

We move all terms to the left:

(y-4)-2(4-y)-(1)=0

We add all the numbers together, and all the variables

(y-4)-2(-1y+4)-1=0

We multiply parentheses

(y-4)+2y-8-1=0

We get rid of parentheses

y+2y-4-8-1=0

We add all the numbers together, and all the variables

3y-13=0

We move all terms containing y to the left, all other terms to the right

3y=13

y=13/3

y=4+1/3

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