(y-4)/5=(y+1)/3

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Solution for (y-4)/5=(y+1)/3 equation:



(y-4)/5=(y+1)/3
We move all terms to the left:
(y-4)/5-((y+1)/3)=0
We calculate fractions
y/()+(-((y+1)*5)/()=0
We calculate terms in parentheses: +(-((y+1)*5)/(), so:
-((y+1)*5)/(
We multiply all the terms by the denominator
-((y+1)*5)
We calculate terms in parentheses: -((y+1)*5), so:
(y+1)*5
We multiply parentheses
5y+5
Back to the equation:
-(5y+5)
We get rid of parentheses
-5y-5
Back to the equation:
+(-5y-5)
We get rid of parentheses
y/()-5y-5=0
We multiply all the terms by the denominator
y-5y*()-5*()=0
We add all the numbers together, and all the variables
y-5y*()=0

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