(y-4)2=(2-y)3

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Solution for (y-4)2=(2-y)3 equation: 



(y-4)2=(2-y)3

We move all terms to the left:

(y-4)2-((2-y)3)=0

We add all the numbers together, and all the variables

(y-4)2-((-1y+2)3)=0

We multiply parentheses

2y-((-1y+2)3)-8=0



We calculate terms in parentheses: -((-1y+2)3), so:

(-1y+2)3

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We get rid of parentheses

2y+3y-6-8=0

We add all the numbers together, and all the variables

5y-14=0

We move all terms containing y to the left, all other terms to the right

5y=14

y=14/5

y=2+4/5

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